These are two separate equations and i need to write all three equations for both, chemical,ionic, and net ionic equations
Please help
1. sodium bromide,NaBr, and silver nitrate, AgNO3.
2. Ammonium phosphate, (NH4)3PO4, and aluminum sulfate, Al2(SO4)3How do you write a chemical equation, an ionic equation and a net ionic equation for the following?
the chemical reaction for sodium bromide,NaBr, and silver nitrate, AgNO3 would be:
NaBr + AgNO3 --%26gt; AgBr + NaNO3
the ionic equation would include ions and would be:
Na^+ +Br^- +Ag^+ +NO3^- --%26gt; AgBr + Na^+ + NO^3-
the net ionic equation would be:
Br^- + Ag^+ --%26gt;AgBr
For Ammonium phosphate, (NH4)3PO4, and aluminum sulfate, Al2(SO4)3, the chemical equation would be:
2(NH4)3PO4 + Al2(SO4)3 --%26gt; 2AlPO4 +
3(NH4)2SO4
The ionic equation would be:
6NH4^+ +2PO4^3- + 2Al^3+ + 3SO4^2-
--%26gt;2AlPO4 + 6NH4^+ + 3SO4^2-
the net ionic equation would be:
PO4^3- + Al^3+ --%26gt; AlPO4How do you write a chemical equation, an ionic equation and a net ionic equation for the following?
The chemical equation would be the normal balanced equation.
An ionic equation is the same equation but with the molecules broken into their ions (ie sodium and bromine instead of sodium bromide).
A net ionic equation shows only the items of the ionic equation that change. For example if you have the ionic equation A(neg) + B(pos) + C(neg) + D(pos) yields AD(precipitate) + B(pos) + C(neg) the net ionic would only include A and D. That is it only includes the elements of the reaction that do not stay in solution and form a precipitate. Check a solubility table to figure out what stays in solution and what does not.
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