How would you find the net ionic equations for these reactions?

The molecular equations are:

HCl (aq) + NaOH (aq) --%26gt; NaCl (aq) + H2O (l)

NH4Cl (aq) + NaOH (aq) --%26gt; NH3 (aq) + NaCl (aq) + H2O (l)

NH3 (aq) + HCl (aq) --%26gt; NH4Cl (aq)



What would the net ionic equations be for these reactions? Thanks in advance to those who answer!How would you find the net ionic equations for these reactions?
1) H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) --%26gt; Na+(aq) + Cl-(aq) + H2O(l)

Now cancel out the same ions, like Cl and Na, but don't split apart water. You can only split whatever's aq, and not gas or liquid. So...H+(aq) + OH-(aq) --%26gt;H2O and don't forget to put aq after each ion, and l after H2O.

2) NH4+(aq) + Cl- (aq)+ Na+ (aq)+ OH-(aq) --%26gt; NH3+ (aq)+ Na+(aq) + Cl- (aq)+ H2O (l)



NH4+(aq) + OH- (aq)--%26gt;NH3+(aq)+ H2O (l)

I'm not too sure if you split apart NH4 and NH3, but I don't think so...



3)NH3 (aq) + HCl (aq) --%26gt; NH4Cl (aq)



N-3(aq) + 3H+(aq) + H+(aq) + Cl-(aq) --%26gt; NH4 + (aq) + Cl- (aq)

The Cl- cancel...How would you find the net ionic equations for these reactions?
HCl is a strong acid and NaOH is a strong base so they completely ionize in water. As does the salt. So Cl, Na, cancel.



H^+^ + OH^-^ ----%26gt; H2O(l)



NH4 ionizes as does NaOH, NaCl. so the Cl, Na, cancel



NH4 + OH^-^ -----%26gt; NH3 + H2O



In this one the HCl and NH4Cl ionize and the Cl's cancel



NH3+ H^+^ ----%26gt; NH4